Answer:
![f_(blue)= (3x10^8 m/s)/(4x10^(-7) m)= 7.5 x10^(14) Hz](https://img.qammunity.org/2021/formulas/physics/college/rbhh045d784ymeuhp2edrnl9h57ckqnzy0.png)
So then our answer would be:
D. 7.50 × 10¹⁴Hz
Step-by-step explanation:
For this case we know the frequency for the blue light, given by the problem:
![\lambda_(blue)= 400 nm](https://img.qammunity.org/2021/formulas/physics/college/4uquoasr0mvfviezguaab6ll9cpuyro1zo.png)
We can convert this into m like this:
![\lambda_(blue)= 400 nm *(10^(-9)m)/(1nm)= 400x10^(-9)m = 4x10^(-7)m](https://img.qammunity.org/2021/formulas/physics/college/j6faqwgibfo2drkkn7jeliia6oto706w5i.png)
We know that the speed of light is a constant and is given by:
![v_(light)= 3x10^(8) (m)/(s)](https://img.qammunity.org/2021/formulas/physics/college/l19wv91yvf54gtvrjsm2mvbknzodlkku21.png)
And assuming that we have a fundamental wave, we need to satisfy the following basic relationship:
![v = \lambda f](https://img.qammunity.org/2021/formulas/physics/college/ub527k4d2ksyn273bkmfqtwcak2tpq6rsx.png)
And if we solve for the frequency from the last formula we got:
![f = (v)/(\lambda)](https://img.qammunity.org/2021/formulas/physics/college/7p1yeal093hcwppycaahtfad4wqky8ywod.png)
Now if we replace the values given we have:
![f_(blue)= (3x10^8 m/s)/(4x10^(-7) m)= 7.5 x10^(14) Hz](https://img.qammunity.org/2021/formulas/physics/college/rbhh045d784ymeuhp2edrnl9h57ckqnzy0.png)
So then our answer would be:
D. 7.50 × 10¹⁴Hz