Answer:
The probability that he makes the free throw in all three attempts is 0.7787.
Explanation:
Let X = number of free throw attempts Steph Curry makes.
The probability that Steph Curry makes a free throw is, p = 0.92.
The number of free throws he gets is, n = 3.
Then the random variable X follows a Binomial distribution with parameters, n = 3 and p = 0.92.
The probability function for binomial is:
![P(X=x)={n\choose x}p^(x)(1-p)^(n-x)](https://img.qammunity.org/2021/formulas/mathematics/high-school/c1nythui7qnsy8ayhdd7m4tnrgcvtpdcjl.png)
The probability that he makes the free throw in all three attempts is:
![P(X=3)={3\choose 3}(0.92)^(3)(1-0.92)^(3-3)\\=1* 0.778688* 1\\=0.778688\\\approx0.7787](https://img.qammunity.org/2021/formulas/mathematics/high-school/9qtlz59rzr9c2nz2mwgni5zzbyajqq2msk.png)
Thus, the probability that he makes the free throw in all three attempts is 0.7787.