Answer:
(C) 6.2 cm
Step-by-step explanation:
We are given that
Frequency of ultra sound,f=5.0 MHz=
![5* 10^6 Hz](https://img.qammunity.org/2021/formulas/physics/college/20eb72gyxpjt0chh6oqe7d7nymui4600gy.png)
By using
![1MHz=10^6 Hz](https://img.qammunity.org/2021/formulas/physics/college/8xftjag16duha3lcpuxokhprsasdagfux9.png)
We know that speed of sound in human tissue,v=1540m/s
Let
be the wavelength of ultrasound .
Then, depth of penetration of ultrasound=
![d=200\lambda](https://img.qammunity.org/2021/formulas/physics/college/ux0rqv4cq21vlzynxwn7kf14wy3r4vr77g.png)
We have to find the approximate depth of penetration of ultrasound.
We know that
![\lambda=(v)/(f)](https://img.qammunity.org/2021/formulas/physics/college/hq71kygldddou7o0fxc9o4re7sdzltb1pg.png)
Using the formula
![d=200* (v)/(f)=200* (1540)/(5* 10^6)](https://img.qammunity.org/2021/formulas/physics/college/niv53foxd7yy1kvmlt7fp0r1492evpkpsv.png)
![d=6.2* 10^(-2) m](https://img.qammunity.org/2021/formulas/physics/college/incxl24ovid9zg7uo74wh7rm5jlrtl6esh.png)
![d=6.2* 10^(-2)* 10^2=6.2* 10^(-2+2)=6.2* 10^0=6.2* 1=6.2 cm](https://img.qammunity.org/2021/formulas/physics/college/syc7mkm2cqs3vo6m37kweh8efbcnb6tomw.png)
By using
![a^x\cdot a^y=a^(x+y)](https://img.qammunity.org/2021/formulas/mathematics/college/bgvhumb7snetqjehzc4zwuye1mh3z8y2cc.png)
![10^0=1](https://img.qammunity.org/2021/formulas/physics/college/8kwmlx1rpe29mtuzn3kgbwsftav3rl8ams.png)
Option C is true.