Question

How much nh3 is needed to react completely with 34g of ch3oh?

Answer 1

18.06 g of ammonia

Step-by-step explanation:

This is the reaction:

NH₃ + CH₃OH → CH₃NH₂ + H₂O

Ratio is 1:1

1 mol of ammonia reacts with 1 mol of methanol.

Let's convert the mass of methanol to moles.

34 g . 1 mol / 32 g = 1.06 moles

We need 1.06 moles of NH₃ whichs is the same to say:

1.06 moles. 17 g / 1 mol = 18.06 g of NH₃

Answer 2

36 g ammonia (NH₃) is required to react with 34 g methanol (CH₃OH)

Step-by-step explanation:

The chemical equation for the described chemical reaction:

CH₃OH + 2NH₃ → product

In this chemical reaction, 2 moles of ammonia (NH₃) reacts with 1 mole of methanol (CH₃OH) to give the product.

Also, the molar mass of methanol = 32 g/mol,

and, the molar mass of ammonia = 17 g/mol

As we know, number of moles = given mass ÷ molar mass

or, given mass = number of moles × molar mass

∴ In the given reaction, the mass of ammonia reacting = 2 mole × 17 g/mol = 34 g

And, the mass of methanol reacting = 1 mole × 32 g/mol = 32 g

Now, to find the amount of ammonia that will react with 34 g methanol:

As, in the given reaction,

34 g ammonia reacts with 32 g methanol

So, the amount of ammonia that reacts with 34 g methanol =
`(34 \, g * 34 \, g)/(32 \, g) = 36 \, g`

Therefore, 36 g ammonia (NH₃) is required to react with 34 g methanol (CH₃OH).