Question

Someone solve this for me please ?

Answer 1

A

Explanation:

Using the tangent and cosine ratios in the right triangle and the exact values

tan30° =
`(1)/(√(3) )` and cos30° =
`(√(3) )/(2)`

tan30° =
`(opposite)/(adjacent)` =
`(x)/(6)` =
`(1)/(√(3) )` ( cross- multiply )

x
`√(3)` = 6 ( divide both sides by
`√(3)` )

x =
`(6)/(√(3) )` ×
`(√(3) )/(√(3) )` =
`(6√(3) )/(3)` = 2
`√(3)`

------------------------------------------------------------

cos30° =
`(adjacent)/(hypotenuse)` =
`(6)/(y)` =
`(√(3) )/(2)` ( cross- multiply )

y
`√(3)` = 12 ( divide both sides by
`√(3)` )

y =
`(12)/(√(3) )` ×
`(√(3) )/(√(3) )` =
`(12√(3) )/(3)` = 4
`√(3)`