Answer:
Explanation:
1 ) b^2 + 8b + 7 = 0
breaking the middle term
=> b^2 + 7b+ b + 7 = 0
=> b ( b+ 7) + 1 (b+7)=0
=> (b+1)(b+7)=0
(b + 1 ) = 0 , (b+7) = 0
b = -1 . b= -7 Answer
2) b^2 + 16b + 64
=> b^2+ 8b + 8b +64 =0
=> b ( b + 8 ) + 8 (b + 8) =0
=> (b + 8 )(b+8) =0
=> b = -8 , b= -8
3) 2p^2 + 2p -4
=> 2p^2 +4p-2p-4
=> 2p (p +2) - 2(p+4)
=> (2p-2)(p+2)=0
=> 2p-2 =0 , => p+2 = 0
=> p = 1 , p= -2
4) n^2 + 4n - 12
=> n^2 + 6n-2n-12=0
=> n(n+6)-2(n+6)=0
=>(n-2)(n+6)=0
=> n-2=0 , n+6=0
n=2 , n= -6
5) a^2 + 11a + 18
=> a^2 + 9a + 2a +18 =0
=> a( a +9) + 2 ( a +9 ) = 0
=> ( a + 2 ) ( a + 9) =0
=> a = -2 , a = -9
6) 5v^2 - 30v + 40
=> 5v^2 - 30v + 40
=> 5 v^2 - 20v - 10v + 40
=> 5 v (v - 4) - 10 ( v -4 )
= > ( v - 4 ) ( 5v - 10)
=> v - 4 = 0 , 5v-10 =0
v = 4 , v =(10/5)
v=4 , v =2
7. B^2+8B+7 —> ( B+1 )( B+7 )
8. N^2+4N-12 —> (N+6)(N-2)
10. B^2+16B+64 —> (B+8)(B+8)
11. A^2+11A+18 —> (A+2)(A+9)
13. 2P^2+2P-4 —> 2(P+2)(P-1)
14. 5V^2-30V+40 —> 5(V-2)(V-4)
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