Question

Can someone help me out with this one plz?

Solve the following systems of equations.

{x=4y-5
{2x+5y=25

x=___

y=___

Answer 1

The answer is:

`x=(75)/(13) \\\\y=(35)/(13)`

Explanation:

Given:

x=4y-5

2x+5y=25

Now, to solve the systems of equations.

`x=4y-5\ \ \ ..........(1)`

`2x+5y=25\ \ \ .......(2)`

Now, to solve by using substitution:

`2x+5y=25`

Substituting the value of
`x` from equation (1) we get:

`2(4y-5)+5y=25\\\\8y-10+5y=25\\\\13y-10=25`

Adding both sides by 10 we get:

`13y=35`

Dividing both sides by 13 we get:

`y=(35)/(13)`

Now, substituting the value of
`y` in equation (1):

`x=4y-5`

`x=4* ((35)/(13)) -5\\\\x=(140)/(13) -5`

`x=(140-65)/(13) \\\\x=(75)/(13)`

Therefore, the answer is:

`x=(75)/(13) \\\\y=(35)/(13)`