Question

Simplify : a)
`√(x) 0.49x^1^8` when x<0

Simplify : b)
`15√(x) 0.16c^1^2` x can be anything

Answer 1

The value of
`√(x)0.49x^(18)` =
`0.49x^{(37)/(2)}`

Explanation:

We have,

`√(x(0.49))x^(18)`

To find, the value of
`√(x(0.49))x^(18)` = ?

∴
`√(x(0.49))x^(18)`

=
`0.7x^{(1)/(2)} x^(18)`

=
`0.7x^{18+(1)/(2)}`

Using the identity,

`a^(m).a^(n)=a^(m+n)`

=
`0.7x^{(36+1)/(2)}`

=
`0.7x^{(37)/(2)}`

Thus, the value of
`√(x(0.49))x^(18)` =
`0.49x^{(37)/(2)}`