Question

An atom of an element weighs 3.38× 10–23 g. What is the atomic mass of this element in atomic mass units?

Answer 1

Answer: The atomic mass of this element in atomic mass units is 20.3

Step-by-step explanation:

According to avogadro's law, 1 mole of every substance weighs equal to molecular mass and contains avogadro's number
`6.023* 10^(23)` of particles.

To calculate the number of moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}`

Let atomic mass of element is X amu

`6.023* 10^(23)` atoms weigh = X amu

1 atom weigh =
`(X)/(6.023* 10^(23))* 1=3.38* 10^(-23)amu`

`X=20.3amu`

Atomic mass of this element in atomic mass units is 20.3