Question

A hill that has a 28.1% grade is one that rises 28.1 m vertically for every 100.0 ml of distance in the horizontal direction. At what angle is such a hill inclined above the horizontal?

Answer 1

`\theta=15.70^\circ`

Step-by-step explanation:

A right triangle is formed, in which the vertical elevation is the opposite cathetus and the horizontal distance is the adjacent cathetus, since we know these two values, we can calculate the angle of inclination using the definition of tangent:

`tan\theta=(opp)/(adj)\\\theta=arctan((opp)/(adj))\\\theta=arctan((28.1m)/(100m))\\\theta=15.70^\circ`