Question

Two electrons are separated by a distance of 1.00 nm and held fixed in place. A third electron, initially very far away, moves toward the other two electrons and stops at the point exactly midway between them. Calculate the speed of the third electron when it was very far away from the other electrons.

Answer 1

The speed of the third electron when it was far away from other electrons is 7 X 10¹⁵m/s

Step-by-step explanation:

qV = 0.5Mv²

where;

V is the potential difference, measured in Volts

q is the charge of the electron in Coulomb's = 1.6 × 10⁻¹⁹ C

Mass is the mass of the electron in kg = 9 × 10⁻³¹ kg

v is the velocity of the electron in m/s

Applying coulomb's law, we determine the Potential difference V

V = kq/r

V = (8.99X10⁹ * 1.6 × 10⁻¹⁹)/(1X10⁻⁹)

V = 14.384 X 10¹⁹ V

The speed of the electron can be determined as follows;

v² = (2qV)/M

v = √(2qV)/M)

v = √(2*1.6 × 10⁻¹⁹* 14.384 X 10¹⁹)/(9 × 10⁻³¹)

v = √(5.1143 X 10³¹) = 7 X 10¹⁵m/s

Therefore, the speed of the third electron when it was far away from other electrons is 7 X 10¹⁵m/s