Answer:
Vapor pressure of solution = 111.98 Torr
Step-by-step explanation:
Colligative property to apply: Lowering vapor pressure
P° - P' = P° . Xm . i
P°, vapor pressure of pure solvent
P', vapor pressure of solution
Xm, mole fraction of solute
i, Van't Hoff factor.
Let's determine the Xm.
Moles of solute = mass / molar mass → 34.2 g / 58.45 g/mol = 0.585 moles
Moles of solvent = 375 g / 18 g/mol = 20.83 moles
Mole fraction = 0.585 mol / 0.585 mol + 20.83 mol → 0.0273
Let's replace the data in the formula:
118.1 Torr - P' = 118.1 Torr . 0.0273 . 1.9
118.1 Torr - 6.12 Torr = P'
Vapor pressure of solution = 111.98 Torr