Answer: First pond= 8.0 mg/L
second pond = 4.2 mg/L
Step-by-step explanation:
Cn/Co = [ 1/ [ 1 + (k*t/n)]]
for the first pond
where Co into the first pond is 20mg/L,
Cn = 20*[ 1/ [ 1+ ((1 x 5)/0.3)]]
Cn = 8 mg/L
into the second pond we calculate the BOD leaving the pond of volume 3million liters
we have Cn = 4.2 mg/L