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Two equivalents of molecular halogen will react with and add to an alkyne. Complete the mechanism and draw the organic product. Include all lone pairs and nonzero formal charges.

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Answer:

The drawing of the mechanism and the organic product is shown below.

Step-by-step explanation:

Alkynes react with bromine to form a dihaloalkene (with an equivalent of the halogen) or a tetrahaloalkane derivative (with two equivalents of the halogen), which is this case. The triple bond adds two halogen molecules as shown in the drawing, an anti addition occurring.

Two equivalents of molecular halogen will react with and add to an alkyne. Complete-example-1
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