Question

A 12.0 V battery is attached to a circuit with a resistor of 5.5 Ohms. The internal resistance of the circuit is 1.75 Ohms. What is the terminal voltage of the circuit?

Answer 1

The end voltage is 9.01 volts.

Step-by-step explanation:

The emf of the battery is 12 volts.

The resistance of the circuit = 1.75 ohms.

The resistance of the applicant attached = 5.5 ohms.

So, total resistance of the circuit =
`1.75 + 5.5` ohms = 7.25 ohms.

According to the equation, the voltage applied is equal to the product of the current and the resistance.

V=iR.

So, 12 =
`i *7.25`.

So, i = 1.66.

Therefore, the voltage at the end of the circuit =
`12 - 1.66*1.75`volts

= 9.01volts.

So the end voltage is 9.01 volts.