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Charge of uniform surface density (0.20 nC/m2 ) is distributed over the entire xy plane. Determine the magnitude of the electric field at any point having z = 2.0 m

User Robina Li
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1 Answer

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Answer:

E= 11.3 N/C.

Step-by-step explanation:

The electric filed at any point on the z-axis is given by the formula


E= (\sigma)/(2\epsilon_0)

here, sigma is the charge density and ε_o is the permitivity of free space.

therefore,


E= (0.2*10^(-9))/(2*8.85*10^(-12))

solving it we get

E= 11.3 N/C.

Hence, the required Electric field is E= 11.3 N/C.

User Avanish Singh
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