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Given the following information about the arithmetic sequence an, find a17.
a3=13
a13=43

User Bojeil
by
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1 Answer

4 votes

Answer:


$ \textbf{a}_{\textbf{17}} \hspace{1mm} \textbf{=} \hspace{1mm} \textbf{55} $

Explanation:

The
$ n^(th) $ term of an arithmetic sequence is given by:


$ \textbf{a}_{\textbf{n}} \hspace{1mm} \textbf{=} \hspace{1mm} \textbf{a} \hspace{1mm} \textbf{+} \hspace{1mm} \textbf{(n - 1)d} $

where a is the first term of the sequence

and d is the common difference.

We are given the
$ 3^(rd) $ and the
$ 13^(th) $ term of the sequence.

We are asked to find the
$ 17^(th) $ term.

From the formula, we can write


$ a_3 = a + (3 - 1)d $


$ \implies 13 = a + 2d \hspace{6mm} \hdots (1) $

Also,
$ a_(13) = a + (13 - 1)d $


$ \implies 43 = a + 12d \hspace{6mm} \hdots (2) $

Now, we solve Equation (1) and (2) for a and d.

Solving we get:

a = 7; d = 3

Therefore,
$ 17^(th) $ term,
$ a_(17) $ can now be calculated.


$ a_(17) = a + (17 - 1)d $


$ \implies a_(17) = 7 + 16(3) $


$ \implies \textbf{a}_{\textbf{17}} \hspace{1mm} \textbf{=} \hspace{1mm} \textbf{55} $

Therefore, the
$ 17^(th) $ term of the sequence is 55.

Hence, the answer.

User Stevenghines
by
5.4k points