Question

The length of a rectangle is 3 less than twice the width. If the area of the rectangle is 50 square inches, choose the equation that could be used to solve for the dimensions.

Answer 1

`w(2w-3)=50`

Step-by-step explanation:

Let the length of the rectangle be
`w` units.

We were given that the length is 3 less than twice the width.

This implies that:
`l=2w-3`

We have that the area of this rectangle is 50 square inches.

Recall that area of rectangle is given by:

`A=lw`

`\implies w(2w-3)=50`

Therefore the required equation is
`w(2w-3)=50`