Question

Calculate the distance olive oil (a lipid) could move in a membrane in 15 seconds assuming the diffusion coefficient is 1 μm2/s. Use the equation where S is distance traveled, t is time, and D is the diffusion coefficient.S = (4Dt)^1/2

Answer 1

Using the equation S = (4Dt)^1/2, the average distance olive oil can move in a membrane in 15 seconds is calculated to be 7.75 micrometers.

Step-by-step explanation:

To calculate the distance that olive oil, a lipid, could move in a membrane in 15 seconds with a diffusion coefficient of 1 μm2/s, we use the equation S = (4Dt)1/2. Plugging in the values, we get S = (4 × 1 μm2/s × 15 s)1/2. We perform the calculation as follows:

• Calculate the product of 4, the diffusion coefficient (D), and time (t): 4 × 1 μm2/s × 15 s = 60 μm2
• Take the square root of 60 μm2 to find the distance: √60 μm2 = 7.75 μm

The average distance that olive oil can move in the membrane in 15 seconds is 7.75 micrometers.

Answer 2

The answer according to the given equation is S = 0.00077 cm

Step-by-step explanation:

According to this equation

S = (4Dt)^1/2

S = (4* 1^e-8 * 15)^0.5

S = 0.00077 cm

According to the Approximation equation for diffusion time

t ≅ S^2 / 2D

S = 0.00055 cm