Question

What is the electric potential V V due to the nucleus of hydrogen at a distance of 5.292 × 10 − 11 m 5.292×10−11 m ?

Answer 1

27.1806500378 V

Step-by-step explanation:

k = Coulomb constant =
`8.99* 10^(9)\ Nm^2/C^2`

q = Charge =
`1.6* 10^(-19)\ C`

r = Distance =
`5.292* 10^(-11)\ m`

Voltage is given by

`V=k(q)/(r)\\\Rightarrow V=8.99* 10^9(1.6* 10^(-19))/(5.292* 10^(-11))\\\Rightarrow V=27.1806500378\ V`

The potential difference is 27.1806500378 V