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What is the electric potential V V due to the nucleus of hydrogen at a distance of 5.292 × 10 − 11 m 5.292×10−11 m ?
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What is the electric potential V V due to the nucleus of hydrogen at a distance of 5.292 × 10 − 11 m 5.292×10−11 m ?

User Superjessi
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1 Answer

6 votes

Answer:

27.1806500378 V

Step-by-step explanation:

k = Coulomb constant =
8.99* 10^(9)\ Nm^2/C^2

q = Charge =
1.6* 10^(-19)\ C

r = Distance =
5.292* 10^(-11)\ m

Voltage is given by


V=k(q)/(r)\\\Rightarrow V=8.99* 10^9(1.6* 10^(-19))/(5.292* 10^(-11))\\\Rightarrow V=27.1806500378\ V

The potential difference is 27.1806500378 V

User CoreDo
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5.1k points
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