Answer : The concentration of a solution with an absorbance of 0.420 is, 0.162 M
Explanation :
Using Beer-Lambert's law :
![A=\epsilon * C* l](https://img.qammunity.org/2021/formulas/chemistry/college/ywdml52jyc3qqdiud7usxqzuq5ij88xu8h.png)
As per question, at constant path-length there is a direct relation between absorbance and concentration.
![(A_1)/(A_2)=(C_1)/(C_2)](https://img.qammunity.org/2021/formulas/chemistry/college/7utp5pap0675ekucp1wn0dn0cc1bzdh4cd.png)
where,
A = absorbance of solution
C = concentration of solution
l = path length
= initial absorbance = 0.350
= final absorbance = 0.420
= initial concentration = 0.135 M
= final concentration = ?
Now put all the given value in the above relation, we get:
![(0.350)/(0.420)=(0.135)/(C_2)](https://img.qammunity.org/2021/formulas/chemistry/college/e9395gv9l65db9efuj8of3kqwmq3sjk7f1.png)
![C_2=0.162M](https://img.qammunity.org/2021/formulas/chemistry/college/unahkhiohnwubwcyrkyo0mu1dkoc88fk48.png)
Thus, the concentration of a solution with an absorbance of 0.420 is, 0.162 M