The maximum distance on the Moon is six times higher than on the Earth for the object with the same angle and take off speed.
Step-by-step explanation:
Let us assume , an Object is thrown with initial Velocity u m/s and angle of θ above the horizontal level. The horizontal and vertical velocities are (x,y)
vₓ = v₀cos θ
= v₀ sinθ
now, the time when the object reaches the maximum height can be calculated from
= v₀ sinθ - at₀ = 0
t₀ = v₀ sinθ/a
thus, the total time in air is two times higher ; t = 2t₀ = 2 (v₀ sinθ) /a
the maximum distance can be calculated from this equation
X = vₓ t= v₀ cos θ x 2 (v₀ sinθ) /a
it implies x is inversely proportional to a.
we know the acceleration on the Moon is 1/6 th of Earth.the ratio between between maximal distance on the moon and on the earth is 6.