Answer:
Solubility of CO2 = 0.045 g/l
Step-by-step explanation:
Using Henry’s law which states that the quantity of an ideal gas that dissolves in a definite volume of liquid is directly proportional to the pressure of the gas.
C = k * Pg
Where C = concentration of the gas
Pg = pressure of the gas
k = proportionality constant
Calculating k,
k = C/Pg
Converting g/100ml to g/l,
0.00412 g/100ml; 0.00412g/100ml * 1000ml/1l
= 0.0412 g/l
Pressure in bar,
Pg = 1.01 bar
k = 0.0412/1.01 bar
= 0.0412 g/l.bar
Molar mass of CO2 = 12 + (16*2)
= 44 g/mol
Molar concentration of CO2 = k/molar mass
= 0.000936 mol/l.bar
Pressure of oxygen = 1.533 bar
Molar mass of O2 = 32 g/mol
Solubility of O2 = molar mass * molar concentration * pressure (bar)
= 32 * 0.000936 * 1.533
= 0.0459 g/l
Pressure in mmHg,
Pg = 760 mmHg
k = 0.0412/760
= 0.000054 g/l.mmHg
Molar mass of CO2 = 12 + (16*2)
= 44 g/mol
Molar concentration of CO2 = k/molar mass
= 0.00000123 mol/l.mmHg
Pressure of oxygen = 1150 mmHg
Molar mass of O2 = 32 g/mol
Solubility of O2 = molar mass * molar concentration * pressure (mmHg)
= 32 * 0.00000123 * 1150
= 0.0453 g/l