Question

I need help with both of them i will give you 25 points
plz help

Answer 1

1)m<DCH =89

2)m<BCD=103

Explanation:

1) We have that:

m<EFB=91 degree.

We want to find m<DCH.

By same side interior angle property:

m<DCH +m<EFB=180

m<DCH +91=180

m<DCH=180-91

m<DCH =89

2) Given that: m<HFG=103, we seek to find m<BCD.

By the alternate exterior angle property:

m<HFG=m<BCD

Therefore

m<BCD=103