Question

Oscilloscopes are found in most science laboratories. Inside, they contain deflecting plates consisting of more-or-less square parallel metal sheets, typically about 2.50 cm on each side and 2.00 mm apart. In many experiments, the maximum potential across these plates is about 30.0 V.

1.For this maximum potential, what is the strength of the electric field between the plates? [V/m]

2.For this maximum potential, what magnitude of acceleration would this field produce on an electron midway between the plates? [m/s^2]

Answer 1

15000 V/m

`2.634467618* 10^(15)\ m/s^2`

Step-by-step explanation:

V = Voltage = 30 V

d = Separation = 2 mm

q = Charge of electron =
`1.6* 10^(-19)\ C`

m = Mass of electron =
`9.11* 10^(-31)\ kg`

Electric field is given by

`E=(V)/(d)\\\Rightarrow E=(30)/(2* 10^(-3))\\\Rightarrow E=15000\ V/m`

The electric field between the plates is 15000 V/m

Acceleration is given by

`a=(qE)/(m)\\\Rightarrow a=(1.6* 10^(-19)* 15000)/(9.11* 10^(-31))\\\Rightarrow a=2.634467618* 10^(15)\ m/s^2`

The acceleration is
`2.634467618* 10^(15)\ m/s^2`