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A closed, rigid tank is lled with a gas modeled as an ideal gas, initially at 27°C and a gage pressure of 300 kPa. The gas is heated, and the gage pressure at the nal state is 367 kPa. Determine the nal temperature, in °C. The local atmospheric pressure is 1 atm.

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Answer:

T₂ =93.77 °C

Step-by-step explanation:

Initial temperature ,T₁ =27°C= 273 +27 = 300 K

We know that

Absolute pressure = Gauge pressure + Atmospheric pressure

Initial pressure ,P₁ = 300+1=301 kPa

Final pressure ,P₂= 367+1 = 368 kPa

Lets take temperature=T₂

We know that ,If the volume of the gas is constant ,then we can say that


(P_2)/(P_1)=(T_2)/(T_1)


{T_2}=T_1* (P_2)/(P_1)

Now by putting the values in the above equation we get


{T_2}=300* (368)/(301)\ K

The temperature in °C

T₂ = 366.77 - 273 °C

T₂ =93.77 °C

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