Question

My sling shot shoots pellets at 50m/s. Find two angles of elevation that can be used to hit a target 65m away. (Assume air resistance is negligible. Assume the gravitational constant ????=10m/s2 for this problem.)

Answer 1

Step-by-step explanation:

Given

velocity of launch
`u=50\ m/s`

Target is
`R=65\m\ away`

Suppose
`\theta` is the launch angle

We know Range of Projectile is

`R=(u^2\sin 2\theta )/(g)`

`65=(50^2* \sin 2\theta )/(9.8)`

`\sin 2\theta =0.254`

because
`\sin \theta =\sin (180-\theta )`

so either
`2\theta =14.71`

`\theta =7.35^(\circ)`

or
`180-2\theta =14.71`

`\theta =82.64^(\circ)`