Question

H(x) = x2 + 1 k(x) = x – 2

(h + k)(2) =


(h – k)(3) =


Evaluate 3h(2) + 2k(3) =

Answer 1

(h + k)(2) = h(2) + k(2) =
`2^(2)` + 1 + 2 - 2 = 4 + 1 = 5

(h - k)(3) = h(3) - k(3) =
`3^(2)` + 1 - (3 - 2) = 10 - 1 = 9

Explanation:

h(x) =
`x^2 + 1`

k(x) = x - 2

(h + k)(2) = h(2) + k(2) =
`2^(2)` + 1 + 2 - 2 = 4 + 1 = 5

(h - k)(3) = h(3) - k(3) =
`3^(2)` + 1 -(3 - 2) = 10 - 1 = 9