Question

A capacitor consists of a set of two parallel plates of area A separated by a distance d. This capacitor is connected to a battery that maintains a constant potential difference V across the plates. If the separation between the plates is doubled, the electrical energy stored in the capacitor will be:_______

a- doubled
b- unchanged
c- quadrupled
d- quartered
e- halved

Answer 1

Answer:e

Step-by-step explanation:

Given

Area of parallel plates is A

distance between plates is d

Potential difference between Plates is V

Capacitance is given by

`C=(\epsilon _0A)/(d)`

If separation is doubled then capacitance become half

`C'=(\epsilon _0A)/(2d)`

`C'=(C)/(2)`

Electrical energy stored in the capacitor is given by

`E=(1)/(2)CV^2`

When distance is doubled

`E'=(1)/(2)* (C)/(2)* V^2`

`E'=(E)/(2)`

Therefore Energy is halved