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A small pumpkin is launched from a very versatile catapult at a variety of speeds and angles. The angles are measured relative to the horizontal. Rank each of the following trials by the maximum height reached by the pumpkin. (1=highest) Consider air resistance to be negligible.

1 2 3 4 Speed: 30.7m/s, Angle: 35.7°
1 2 3 4 Speed: 47.9m/s, Angle: 33.2°
1 2 3 4 Speed: 21.8m/s, Angle: 67.7°
1 2 3 4 Speed: 7.7m/s, Angle: 62.1°

User Abhinav
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1 Answer

3 votes

Answer:

Step-by-step explanation:

Maximum height of a projectile


H_(max)=(u^2\sin ^2\theta )/(2g)

(1)
u=30.7\ m/s


\theta =35.7^(\circ)


H_1=(30.7^2* \sin ^2(35.7))/(2* 9.8)


H_1=16.37\ m

(2)
u=47.9\ m/s


\theta =33.2^(\circ)


H_2=(47.9^2* \sin ^2(33.2))/(2* 9.8)


H_2=35.09\ m

(3)
u=21.8\ m/s


\theta =67.7^(\circ)


H_3=(21.8^2* \sin ^2(67.7))/(2* 9.8)


H_3=20.75\ m

(4)
u=7.7\ m/s


\theta =62.1^(\circ)


H_4=(7.7^2* \sin ^2(62.1))/(2* 9.8)


H_4=2.36\ m

Therefore height reached by pumpkin can be arranged as


H_4<H_1<H_3<H_2

User Jaswanth
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