Question

I need help please and thank you
(A AND B ARE NOT ANSWERS THEY ARE SEPARATE PROBLEMS)

Answer 1

Part a) Wayne's savings before he spent $28 was $31.08

Part b) Stef's savings after she spent $28 was $9.29

Explanation:

Part a)

Let

x ----> original amount of Wayne's savings

y ----> original amount of Stef's savings

we know that

Original ratio

`(x)/(y)=(5)/(6)`

`x=(5)/(6)y` ----> equation A

After spending $28 each

`(x-28)/(y-28)=(1)/(4)`

Multiply in cross

`4x-112=y-25\\y=4x-112+25`

`y=4x-87` ----> equation B

substitute equation A in equation B

`y=4((5)/(6)y)-87`

solve for y

`(20)/(6)y-y=87`

`(7)/(3)y=87`

`y=37.29`

Find the value of x

`x=(5)/(6)(37.29)=31.08`

so

The original amount of Wayne's savings was $31.08 and the original amount of Stef's savings was $37.29

therefore

Wayne's savings before he spent $28 was $31.08

Part b) Find Stef's savings after she spent $28

Subtract $28 from the original savings

so

$37.29-$28=$9.29

therefore

Stef's savings after she spent $28 was $9.29