Question

Please help me with this question, image attached

Answer 1

`W=(x-6)\ m`

Explanation:

we know that

The area of rectangle is equal to

`A=LW`

we have

`A=(x^(2) -11x+30)\ m^2`

`L=(x-5)\ m`

substitute the given values in the formula of area

`(x^(2) -11x+30)=(x-5)W`

Remember that

`x^(2) -11x+30=(x-5)(x-6)` ----> by completing the square

substitute

`(x-5)(x-6)=(x-5)W`

Simplify

`W=(x-6)\ m`