Question

the length of a rectagle is 5 in longer than its width. if the perimeter of the rectangle is 56 in, find its length and width

Answer 1

Explanation:

Let the width of the rectangle = x

As length is 5 inches longer than width, we have to add 5 to width

Length = x + 5

Perimeter of ractangle = 56 in

2* (length + width) = 56

2*( x + 5 + x) = 56

2* (2x + 5) = 56

Use distributive property: a*(b +c) =(a*b) + (a * c)

2*2x + 2*5 = 56

4x + 10 = 56

Subtract 10 from both sides

4x = 56- 10

4x = 46

Divide both sides by 4

x = 46/4

x = 11.5

Width = 11.5 in

length = 11.5 + 5

= 16.5 in