Question

A car went 60 km in 5/6 of an hour while a second car went 54 km in 2/3h. Which car was faster? How many times faster?

Answer 1

The car that went 54 km in 2/3h was faster, 5/4 times faster than the other car

Step-by-step explanation:

Average speed of a car is the ratio between the displacement
`\Delta x` and the time (t) it takes to do that displacement:

`V_(avg)=(\Delta x)/(t)`

So, for the first car:

`V_(avg1)=(60km)/((5h)/(6)) =72(km)/(h)` (1)

for the second car we have:

`V_(avg2)=(60km)/((2h)/(3)) =90(km)/(h)` (2)

So, the second cart is faster than the first one. To find how many times divide speed 2 by speed 1:

`(90)/(72)=(5)/(4)`