Answer:
Probability, P(n) = 3/8
Explanation: Let standard delivery be S and express delivery be E.
I) When the parcels were sent:
S(n) = 75/100 and E(n) = 25/100
II) When the parcels arrived:
S(n)← = 80/100 and E(n)← = 95/100
The probability a record of a parcel delivery is chosen, P(n) = S(n)*E(n) + E(n)*S(n) = 75/100*25/100 + 25/100*75/100
P(n) = 3/16 + 3/16 = 6/16
∴ P(n) = 3/8