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A manometer containing oil (rho = 850 kg/m3) is attached to a tank filled with air. If the oil-level difference between the two columns is 110 cm and the atmospheric pressure is 98 kPa, determine the absolute pressure of the air in the tank.

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Answer:


P_(abs)=107172.35Pa\\ P_(abs)=107.172kPa

Step-by-step explanation:

Given data


P_(a)=98kPa\\ p_(oil)=850kg/m^(3)\\ h=110cm=1.10m

To find absolute pressure of air in the tank.We must find the pressure athe parallel point from the right tube

So


P_(abs)=P_(a)+hp_(oil)g\\P_(abs)=98000Pa+(1.10m*850kg/m^(3)*9.81 )\\P_(abs)=107172.35Pa\\ P_(abs)=107.172kPa

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