Register

Log3 (7x - 1) = log2 (5x +17) SOLVE.

Log3 (7x - 1) = log2 (5x +17) SOLVE.
131k views
1 vote
Log3 (7x - 1) = log2 (5x +17)
SOLVE.

User Luan Naufal
by
8.8k points

1 Answer

5 votes

Answer:

x=1.113317

Explanation:

User Stuart Robson
by
7.6k points
← Prev Question Next Question →

Related questions

User Tombala
asked Mar 24, 2024 127k views
Given that log3=0.4771 and log5=0.6990, evaluate the value of log1.35+log2.25
Tombala asked Mar 24, 2024
by Tombala
8.3k points
1 answer
0 votes
127k views
User Leaha
asked Nov 9, 2024 57.0k views
Log3- log2÷log 9 - log4​
Leaha asked Nov 9, 2024
by Leaha
8.3k points
1 answer
4 votes
57.0k views
User Goodwine
asked Nov 14, 2024 40.9k views
Given that log2 = x and log3 = y, express log60 in terms of x and y
Goodwine asked Nov 14, 2024
by Goodwine
8.1k points
1 answer
2 votes
40.9k views
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
Link Copied!