Answer:
v = 0.2035 m/s
Step-by-step explanation:
given,
Amplitude,A = 0.0127 m
Frequency, f = 2.55 Hz
maximum speed of the needle = ?
we know,
x = A cos ω t
velocity of the motion
v = - A ω sin ω t
for maximum speed
sin ω t = 1
v = - A ω
ω = 2 π f
now,
v = A 2 π f
v = 0.0127 x 2 π x 2.55
v = 0.2035 m/s
Hence, the maximum speed of the needle is equal to 0.2035 m/s