Answer:
![y=-(74)/(21)x+452](https://img.qammunity.org/2021/formulas/mathematics/high-school/za2ltxs8526aoco72p6nz12m1ggkrblzkm.png)
Explanation:
Given:
The level of a lake is falling linearly.
On Jan 1, the level is 452 inches
On Jan 21, the level is 378 inches.
Now, a linear function can be represented in the form:
![y=mx+b](https://img.qammunity.org/2021/formulas/mathematics/middle-school/yj5waqmoy4i54laybzhhshd88hyo5w5rj5.png)
Where, 'm' is the rate of change and 'b' is initial level
![x\to number\ of\ days\ passed\ since\ Jan\ 1](https://img.qammunity.org/2021/formulas/mathematics/high-school/gj0e5oqdajc7qsklsgmz0e74w63dkggu01.png)
![y\to Lake\ level](https://img.qammunity.org/2021/formulas/mathematics/high-school/gtsj25984js1ogulq5xd5y7kiygzos6nxe.png)
So, let Jan 1 corresponds to the initial level and thus b = 452 in
Now, the rate of change is given as the ratio of the change in level of lake to the number of days passed.
So, from Jan 1 to Jan 21, the days passed is 21.
Change in level = Level on Jan 21 - Level on Jan 1
Change in level = 378 in - 452 in = -74 in
Now, rate of change is given as:
![m=(-74)/(21)](https://img.qammunity.org/2021/formulas/mathematics/high-school/dz273uvz6r8kryv4jd85zj4uhr9msrqb3q.png)
Hence, the function to represent the lake level is
![y=-(74)/(21)x+452](https://img.qammunity.org/2021/formulas/mathematics/high-school/za2ltxs8526aoco72p6nz12m1ggkrblzkm.png)
Where, 'x' is the number of days passed since Jan 1.