Question

A sample of nitrogen gas exerts a pressure of 9.80 atm at 32 C. What would its temperature be (in C) when its pressure is increased to 11.2 atm?

Answer 1

T₂ = 111.57 °C

Step-by-step explanation:

Given that

Initial pressure P₁ = 9.8 atm

T₁ = 32°C = 273 + 32 =305 K

The final pressure P₂ = 11.2 atm

Lets take the final temperature = T₂

We know that ,the ideal gas equation

If the volume of the gas is constant ,then we can say that

`(P_2)/(P_1)=(T_2)/(T_1)`

`T_2=(P_2)/(P_1)* T_1`

Now by putting the values in the above equation ,we get

`T_2=(11.2)/(9.8)* 305\ K`

`T_2=348.57\ K`

T₂ = 384.57 - 273 °C

T₂ = 111.57 °C