Question

Combination (Synthesis) Reactions
pls help!

Answer 1

1. CaO + H₂O
`\rightarrow` Ca(OH)₂

2. P₄ + 5O₂
`\rightarrow` P₂O₅

3. 2Ca + O₂
`\rightarrow` 2CaO

4. 8Cu + 2S₈
`\rightarrow`
`8CuS_2`

5. CaO + H₂O
`\rightarrow` Ca(OH)₂

6. S₈ + 8O₂
`\rightarrow` 8SO₂

7. 3H₂ + N₂
`\rightarrow` 2NH₃

8. H₂ + Cl₂
`\rightarrow` 2HCl

9. 16Ag + S₈
`\rightarrow` 8Ag₂S

10. 4Cr + 3O₂
`\rightarrow` 2Cr₂O₃

11. 2Al + 3Br₂
`\rightarrow` 2AlBr₃

12. 2Na + I₂
`\rightarrow` 2NaI

13. 2H₂ + O₂
`\rightarrow` 2H₂O

14. 4Al + 3O₂
`\rightarrow` 2Al₂O₃

1. CaO + H₂O -> Ca(OH)₂: The balanced equation is CaO + H₂O
`\rightarrow` Ca(OH)₂. This chemical equation is already balanced, as there is an equal number of calcium (Ca), oxygen (O), and hydrogen (H) atoms on both sides.

2. P₄ + O₂ -> P₂O₅: The balanced equation is P₄ + 5O₂
`\rightarrow` P₂O₅. Balancing involves placing a coefficient of 5 in front of O₂ to ensure an equal number of phosphorus (P) and oxygen (O) atoms on both sides.

3. Ca + O₂ -> CaO: The balanced equation is 2Ca + O₂
`\rightarrow` 2CaO. By placing a coefficient of 2 in front of Ca and CaO, the number of calcium (Ca) and oxygen (O) atoms is balanced.

4. Cu + S₈ -> CuS: The balanced equation is 8Cu + 2S₈
`\rightarrow`
`8CuS_2`. By placing a coefficient of 8 in front of Cu and a coefficient of 2 in front of S, the number of calcium (Cu) and oxygen (S) atoms is balanced.

5. CaO + H₂O -> Ca(OH)₂: The balanced equation is CaO + H₂O
`\rightarrow` Ca(OH)₂, as the number of calcium (Ca), oxygen (O), and hydrogen (H) atoms is already equal on both sides.

6. S₈ + O₂ -> SO₂: The balanced equation is S₈ + 8O₂
`\rightarrow` 8SO₂. Balancing involves placing a coefficient of 8 in front of O₂ to ensure an equal number of sulfur (S) and oxygen (O) atoms on both sides.

7. H₂ + N₂ -> NH₃: The balanced equation is 3H₂ + N₂
`\rightarrow` 2NH₃. By placing coefficients of 3, 1, and 2 in front of H₂, N₂, and NH₃ respectively, the equation is balanced.

8. H₂ + Cl₂ -> 2HCl: The balanced equation is H₂ + Cl₂
`\rightarrow` 2HCl. Balancing involves placing a coefficient of 2 in front of (HCl) to ensure an equal number of hydrogen (H) and chlorine (Cl) atoms on both sides.

9. Ag + S₈ -> Ag₂S: The balanced equation is 16Ag + S₈
`\rightarrow` 8Ag₂S. By placing a coefficient of 16 in front of Ag and a coeffiecient of 8 in front of the product of Ag and S, so the number of calcium (Ag) and oxygen (S) atoms is balanced.

10. Cr + O₂ -> Cr₂O₃: The balanced equation is 4Cr + 3O₂
`\rightarrow` 2Cr₂O₃. Balancing involves placing coefficients of 4 and 3 in front of (Cr) and (O₂) respectively to equalize the number of chromium (Cr) and oxygen (O) atoms.

11. Al + Br₂ -> AlBr₃: The balanced equation is 2Al + 3Br₂
`\rightarrow` 2AlBr₃. Balancing involves placing coefficients of 2 and 3 in front of Al and Br₂ respectively to ensure an equal number of aluminum (Al) and bromine (Br) atoms.

12. Na + I₂ -> NaI: The balanced equation is 2Na + I₂
`\rightarrow` 2NaI, as coefficients of 2 are placed in front of Na and NaI to achieve a balanced reaction.

13. H₂ + O₂ -> 2H₂O: The balanced equation is 2H₂ + O₂
`\rightarrow` 2H₂O. Balancing involves placing coefficients of 2 in front of H₂ and H₂O to ensure an equal number of hydrogen (H) and oxygen (O) atoms on both sides.

14. Al + O₂ -> Al₂O₃: The balanced equation is 4Al + 3O₂
`\rightarrow` 2Al₂O₃. Balancing involves placing coefficients of 4 and 3 in front of Al and O₂ respectively to equalize the number of aluminum (Al) and oxygen (O) atoms.

Answer 2

Answer: 1. CaO + H2O => Ca(OH)2

2. P4 + 5O2 => 2P2O5

3. 2 Ca + O2 => 2 CaO

4. 8 Cu + S8 => 8 CuS

5. CaO + H2O => Ca(OH)2

6. S8 + 8 O2 => 8 SO2

7. 3 H2 + N2 => 2 NH3

8. H2 + Cl2 =>2 HCl

9. 16 Ag + S8 => 8 Ag2S

10. Cr + O2 => 2Cr2O3

11. 2Al + 3Br2 => 2AlBr3

12. 2Na + I2 => 2NaI

13. 2H2 + O2 =>2 H2O

14. 4 Al + 3O2 => 2 Al2O3

Step-by-step explanation: