Answer:
given,
reaction time.t_r = 0.50 s
deceleration of the car = 6 m/s²
initial speed,v = 20 m/s
distance at which the car stop = ?
distance travel by the car in reaction time
d= v x t_r
d = 20 x 0.5 = 10 m
using equation of motion
distance travel to stop the car
v² = u² + 2 a s
0² = 20² - 2 x 6 x s
12 s = 400
s = 33.33 m
Total distance travel by the car
D = 10 + 33.33
D = 43.33 m
Hence, the car stops before to avoid collision.