GF = 11, GE = 28, HF = 14,
![DG=5\sqrt3](https://img.qammunity.org/2021/formulas/mathematics/middle-school/kdee9wu3s0vzu8w7ttvqzw8k0fzwfvlix9.png)
Solution:
Given data:
DE = 11, GH = 14
In rectangle, opposite sides are equal.
DE = GF
GF = 11
Property of a rectangle:
The diagonals of a rectangle are equal in length and they bisect each other.
Half of diagonal GE = GH = 14
GE = 2 × GH
= 2 × 14
GE = 28
HF is also a half of the diagonal DF.
By property of a rectangle, GH = HF
HF = 14
Diagonal of a rectangle formula:
![D=\sqrt{\text{length}^2+\text{breadth}^2}](https://img.qammunity.org/2021/formulas/mathematics/middle-school/7o800e3drptzriefersm8qb75uwl0yzpte.png)
![14=√(DG^2+11^2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/tmfapr18ola8bil3klvefivcbfug357d0b.png)
Squaring on both sides, we get
![196={DG^2+121}](https://img.qammunity.org/2021/formulas/mathematics/middle-school/cc427kzu3utend0k8hpus7vfrozd8rtyke.png)
![{DG^2=196-121}](https://img.qammunity.org/2021/formulas/mathematics/middle-school/kzcq4fror2mw4jv50qu4ldg23xm75jbeic.png)
![{DG^2=75}](https://img.qammunity.org/2021/formulas/mathematics/middle-school/wo6s7qgxf8my7p9qeq9xmm5v3s3cgld3ob.png)
Taking square root on both sides, we get
![DG=5\sqrt3](https://img.qammunity.org/2021/formulas/mathematics/middle-school/kdee9wu3s0vzu8w7ttvqzw8k0fzwfvlix9.png)
Hence GF = 11, GE = 28, HF = 14,
.