Question

A 700 g peregrine falcon dives toward the ground from a height of 80 m and has a kinetic energy of 2,835 J. What is its speed?

Answer 1

Kinetic energy is gven by

`Kinetic Energy = (1)/(2) mv^(2)`

Hence the velocity can be found by
`v^(2) = (2KE)/(m)`

or
`\sqrt{(2(2835J))/(0.7Kg) }` =
`\sqrt{8100(m^(2) )/(s^(2) ) }` = 90m/s

Step-by-step explanation:

The kinetic energy is the energy due to motion and is given by the kinetic energy equation KE = 1/2mv^2

It is the energy required to stop a body in motion and as seen from the equation, objects with large speed or mass have larger amount of kinetic energy or a large object effect can be made milder by lowering its speed so also a small object can increase its effect, for example a bullet by increasing its speed