1 Answer

Edonbajrami · Answer 1 · 2021-02-13T13:04:46+0000

Answer:

Step-by-step explanation:

Given

Man walks 17.5 m straight to west 17.5 m

So position vector is given by

$\vec{r_1}=-17.5\hat{i}$

Now he walks 22 m North

so position vector is

$r_(21)=22\hat{j}$

Position of man from initial Position

$\vec{r_(2)}=\vec{r_2}-\vec{r_1}$

$\vec{r_(2)}=22\hat{j}-(-17.5\hat{i})$

$\vec{r_(2)}=17.5\hat{i}+22\hat{j}$

So Magnitude of distance is given by

$|\vec{r_(2)}|=√(17.5^2+22^2)$

$|\vec{r_(2)}|=28.11\ m$

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