Question

Doc Inmaking is thinking about the density of liquid water (d = 0.99823 g/mL at 20 °C) compared to the density of ice (0.9168 g/mL at 0 °C). His favorite water bottle has a total volume of 300 mL. He fills it with exactly 288 mL of water at 20 °C. He tightens the lid and puts the bottle in the freezer. What mass of water did Doc placed in the bottle? (Three significant digits, unit of g.)

Answer 1

The mass of water at 20 °C with a density of 0.99823 g/mL that Doc placed in the bottle is 287 g when rounded to three significant digits.

Step-by-step explanation:

The mass of water Doc placed in the bottle can be calculated using the density of liquid water at 20 °C, which is 0.99823 g/mL. Given he filled it with exactly 288 mL of water, the mass of the water is calculated by multiplying the volume by the density: The mass of water at 20 °C with a density of 0.99823 g/mL that Doc placed in the bottle is 287 g when rounded to three significant digits.

Mass = volume × density

Mass = 288 mL × 0.99823 g/mL

Mass = 287.63064 g

Since we are asked to provide the mass to three significant digits, the mass of water Doc placed in the bottle is 287 g.

Answer 2

The mass of water did Doc placed in the bottle is 288 grams.

Step-by-step explanation:

Mass of water filled in water bottle = M

Volume of the water filled in water bottle = V = 288 mL

Density of the water at 20°C , d= 0.99823 g/ml

`D=(M)/(V)`

`M=D* V=0.99823 g/ml* 288 mL=287.49024 g\approx 288 g`

The mass of water did Doc placed in the bottle is 288 grams.