Question

A lightbulb with an intrinsic resistance of 270 \OmegaΩ is hooked up to a 12-volt battery. How much power is output by the lightbulb? Give your answer out to the thousandths place in units of watts (W).

Answer 1

P = 0.533 W

Step-by-step explanation:

given,

Resistance of the bulb, R = 270 Ω

Potential of the battery, V= 12 V

Power output of the bulb = ?

we know,

P = I² R

also, V = IR

`P = (V^2)/(R)`

`P =(12^2)/(270)`

`P =(144)/(270)`

P = 0.533 W

Hence, the Power delivered by the bulb is equal to 0.533 W.