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Joe traveled against the wind in a small plane for 3hours. The return trip with the wind took 2.8 hours. Find the speed of the wind to the nearest tenth if the speed of the plane in still air is 180 mph.

User Rebeka
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1 Answer

2 votes

Answer: the rate of the wind is 6.2 mph

Explanation:

Let x represent the rate of the wind.

Joe traveled against the wind in a small plane for 3hours. If the speed of the plane in still air is 180 mph, then the total speed with which the plane flew is

(180 - x) mph

Distance = speed × time

Therefore, distance travelled against the wind is

3(180 - x)

= 540 - 3x - - - - - - - - - - - - - -1

The return trip with the wind took 2.8 hours.

the total speed with which the plane flew is

(180 + x) mph

Therefore, distance travelled with the wind is

2.8(180 + x)

= 504 + 2.8x - - - - - - - - - - - - - -2

Since the distance is the same, then

540 - 3x = 504 + 2.8x

540 - 504 = 2.8x + 3x

5.8x = 36

x = 36/5.8 = 6.2

User DGK
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