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How much thermal energy needs to be added to 0.455 kg of benzene to heat it from 30*c to 50*c

1 Answer

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15834 joules is the thermal energy required.

Step-by-step explanation:

Specific heat capacity of benzene= 1.74 J/gK or 1740 J/Kg K

mass of benzene = 0.455 kg

temperature change= 50-30

= 20 degrees

From the formula:

Specific heat capacity= thermal energy/ (mass)*(temperature change)

thermal energy= 0.455* 1740*20 ( speicfic heat of benzene is converted

to joules per gram)

= 15834 joules

User J  Calbreath
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