Question

A load consists of a 70-Ω resistor in parallel with a 90-μF capacitor. If the load is connected to a voltage source vs(t) = 160cos 2000t, find the average power delivered to the load.

Answer 1

Power delivered by the source will be 182.912 watt

Step-by-step explanation:

We have given a load is consist of a resistor of 70 ohm in parallel with
`90\mu F` capacitance

Voltage source is given
`v_s(t)=160cos(2000t)`

So maximum value of voltage source is 160 volt

So rms value
`v_(r)=(v_m)/(√(2))=(160)/(1.414)=113.154volt`

We know that average power delivered by the source will be equal to average power absorbed by the resistor

So power absorbed by the resistor
`P=(v_r^2)/(R)=(113.154^2)/(70)=182.912watt`

So power delivered by the source will be 182.912 watt